Math

it's right! quick calculus lesson:

f(x) = (4x+2a-10)/(x^2+6a^2+6)
if we're trying to find the derivative of a fraction (given f(x) = g(x)/h(x)), then this formula would be applied:

f'(x) = (h(x)*g'(x) - g(x)*h'(x))/(h(x)^2)

in this scenario g(x) = 4x+2a-10 and h(x) = x^2+6a^2+6

if we assume "a" is a constant then g'(x) = 4, h'(x) = 2x

so putting it all together (4(x^2+6a^2+6)-2x(4x+2a-10))/(x^2+6a^2+6)^2

which is what the textbook in the panel says :)! you're welcome if you're in calculus and needed this lol

I completely forgot abt derivatives. I thought he was trying to find the beginning of the unsolved problem. I forgot the name however it’s when the question gives u the solved answer and u have to unsolve it? sorry I don’t know how to put it into terms but thank u

integrals? and lol...no problem. i'm in the calc 2 trenches

Yes! Sorry I haven’t done calc1 just pre calc